Question

Mr Prakash has given a contract
to fence his field. He spend Rs 4200
at the rate of Rs 150 per metre.
Find the perimeter of the field. If
the field is 9 m long. find its breadth


Please write in details what we have to do here and to the best answer I will mark as brainliest

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Total cost of fencing : Rs.4200

Rate : 150 per m.

Perimeter of rectangular :

2(Length + Breadth)

= 4200/150

=28

Hence : Length + breadth : 28/2

= 14

Now Length of feild = 9

Breadth = 14 9 = 5m

Hope helpful for you

Answer 2

Appropriate Question :-

Mr Prakash has given a contract to fence his rectangular field. He spend Rs 4200 at the rate of Rs 150 per metre.

Find the perimeter of the field, if the field is 9 m long. Find its breadth.

$\large\underline{\sf{Solution-}}$

Given that,

Mr. Prakash spend Rs 4200 at the rate of Rs 150 per metre

So, it means Perimeter of rectangular field is

$\rm \: Perimeter = \dfrac{4200}{150} = 28 \: m$

Now, we have

Perimeter of rectangular field = 28 m

Length of rectangular field = 9 m

We know, Perimeter of rectangular field is given by

$\rm \: Perimeter = 2(Length + Breadth)$

$\rm \: 28 = 2(9 + Breadth)$

$\rm \: 14 = 9 + Breadth$

$\rm \: Breadth = 14 - 9$

$\rm\implies \:Breadth = 5 \: m$

$\rule{190pt}{2pt}$

Remark :- How we get Perimeter

$\red{\rm \: Rs \: 150 \: is \: the \: cost \: to \: fence \: = \: 1 \: m}$

$\red{\rm \: Re \: 1 \: is \: the \: cost \: to \: fence \: = \: \frac{1}{150} \: m}$

So,

$\red{\rm \: Rs \: 4200 \: is \: the \: cost \: to \: fence \: = \: \frac{4200}{150} = 28 \: m}$

$\rule{190pt}{2pt}$

Additional Information :-

$\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}$