Mr. Rajesh assumed that the time taken for 10 cm' of CO2 to be formed from a reaction
between equal volume of acid solutions and 1.0 g of calcium carbonate is affected by the
pH of acid solution. Mr. Rajesh tested his hypothesis and represented his results in the
graph below.
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(i)Will lumps of CaCO3 react faster or slower than powdered CaCO3?
(ii) What will be time taken to collect 10cm of CO, at pH = 5.0?
(in)What is the nature of CaCO3 salt and what will happen if acid with pH = 6.5 is added
Answers
Answer:
(i) The large lump of CaCO3 has a small surface area relative to the same mass of powdered CaCO3. This means that more particles of CaCO3 will be in contact with HCl in the powdered CaCO3 than in the lumps. As a result, there can be more successful collisions per unit time and the reaction of powdered CaCO3 is faster.
(iii)calcium carbonate has a pH greater then 7,it's considered a base.
If we add mild acid in mild base then compound became neutral. if acid with pH=6.5 is added to CaCo3 then the compound became neutral
Answer:
(i) The big lump of CaCO3 has a small floor vicinity relative to the identical mass of powdered CaCO3. This method that extra debris of CaCO3 can be in touch with HCI withinside the powdered CaCO3 than withinside the lumps. As a result, there may be extra a success collisions consistent with unit time and the response of powdered CaCO3 is faster.
(iii)Calcium carbonate has a pH extra then 7,it is taken into consideration a base.I
Explanation:
(i) The big lump of CaCO3 has a small floor vicinity relative to the identical mass of powdered CaCO3. This method that extra debris of CaCO3 can be in touch with HCI withinside the powdered CaCO3 than withinside the lumps. As a result, there may be extra a success collisions consistent with unit time and the response of powdered CaCO3 is faster.
(iii)Calcium carbonate has a pH extra then 7,it is taken into consideration a base.
If we upload slight acid in slight base then compound have become neutral. if acid with pH=6.five is introduced to CaCo3 then the compound have become neutral.
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