Mr. Raju lent out a certain sum on simple interest and the same sum on compound interest at a certain rate
of interest per annum. If the ratio between the difference of compound interest and simple interest of 2
years and that of 3 years is 10 : 31, what is the rate of interest per annum?
Answers
Given :-
- Mr. Raju lent out a certain sum on simple interest and the same sum on compound interest at a certain rate
- of interest per annum.
- The ratio between the difference of compound interest and simple interest of 2 years and that of 3 years is 10 : 31 .
To Find :-
- what is the rate of interest per annum ?
Solution :-
we know that,
- Difference between the compound interest and simple interest for 2 years at same Principal and same rate of interest is = { Principal * (rate)² } / (100)²
- Difference between the compound interest and simple interest for 3 years at same Principal and same rate of interest is = [ {principal * (rate)² * (300 + rate) } / (100)³ ]
Let us assume that, certain sum is Rs.P and rate of interest is R % per annum.
given that,
→ (Difference between CI and SI for years) / (Difference between CI and SI for years) = 10 / 31
Putting all values in above told formula we get,
→ [{P * (R)²} / (100)²] / [ {P * (R)² * (300 + R) } / (100)³ ] = 10/31
→ {(PR²)/(100)²} * [(100)³/{PR²(300+R)}] = 10/31
→ 100 / (300 + R) = 10/31
cross - Multiply,
→ 10(300 + R) = 3100
dividing both sides by 10,
→ 300 + R = 310
→ R = 310 - 300
→ R = 10% (Ans.)
Hence, Rate of interest per annum is 10% .
See how to prove formula of Difference between the compound interest and simple interest for 3 years at same Principal and same rate of interest :-
Difference between si and ci for 3 years formula
https://brainly.in/question/16133467 .
Given : Mr. Raju lent out a certain sum on simple interest and the same sum on compound interest at a certain rate of interest per annum.
the ratio between the difference of compound interest and simple interest of 2 years and that of 3 years is 10 : 31
To Find : what is the rate of interest per annum
Solution:
Let say Amount = 100P
Simple interest in 2Years = 100P * R * 2 / 100 = 2PR
Compound interest in 2 Years = 100P(1 + R/100)² - 100P
= 100P ( R²/100² + 2R/100)
= 2PR + P R²/100
Difference in Interest in 2 Years = 2PR + P R²/100 - 2PR
= P R²/100
Simple interest in 3Years = 100P * R * 3 / 100 = 3PR
Compound interest in 3 Years = 100P(1 + R/100)³ - 100P
= 100P ( 1 + R³/100³ + 3R²/100² + 3R/100) - 100P
= PR³/100² + 3PR²/100 + 3PR
Difference on interest in 3 Years = PR³/100² + 3PR²/100 + 3PR - 3PR
= PR³/100² + 3PR²/100
= PR²/100( R/100 + 3)
(P R²/100 ) / (P R²/100)( 3 + R /100) = 10/31
=> 31 = 10 ( 3 + R/100)
=> 31 = 30 + R/10
=> 1 = R/10
=> R = 10
rate of interest per annum = 10 %
Taking P = 100
Year SI CI Difference
1 10 10 0
2 20 21 1
3 30 33.1 3.1
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