Question

mr.ram borrow₹ ₹20000 for2 year compounded annual the rate of interest for the two successive yearate 9% and 10% respectively if the rate repays ₹1200 at the end of first year ₹1660 at the end of second year find the amount outstanding at the beginning of the third year​

Answer 1

Thus C.I per 3rd year is ₹ 21000

Step-by-step explanation:

Principal amount = ₹ 2000

Time "t" = 2 years

r1 = 90 %

r2 = 10 %

I = P r t / 100

I = 20,000 x 91 x 9 / 100 = 1800

A = 21800 - 1200

A =  ₹ 20600

I = Prt / 100

I = 20600 x 1 x 10 / 100

A = 20600 + 2060

A = 22660

Compound interest pert 3rd year = 22660 - 1660 = ₹ 21000

Thus C.I per 3rd year is  ₹ 21000

Answer 2

Given:

Principle= ₹20000

Rate of interest for first year = 9%

rate of interest for second year = 10%

To find:

Amount at the beginning of the third year.

Solution:

1) This is the case of the different rate of interest in different year so we will calculate it separately.

2) Amount for the first year

• $A=P(1+\frac{R}{100} )^{T}$

• $A=20000(1+\frac{9}{100} )^{1}$

• A = 200×109

• A = 21800

Ram repays ₹1200 so amount will be ₹23000.

3) Amount for second year

• $A=P (1+\frac{R}{100} )^{T}$

• $A=23000 (1+\frac{10}{100} )^{1}$

• A = 230×110

• A = 25300

Ram repays ₹1660 so amount will be ₹26960.

Amount at the beginning of the third year is ₹26960.