Question

Mr Ram borrow Rs 20000 for 2 years compounded annually the rate of interest for the two successive year and 9% and 10% respectively if he Ritesh rupees 1200 at the end of first year Rupees 1660 at the end of second year find the amount outstanding at the beginning of the third year ​

Answer 1

Answer:

Step-by-step explanation:

P=20,000

R= 9%

T=1 yr

SI =prt/100

= 20000*9*1/100

1800

Returns rupees at the end of 1st year

20000+1800-1200 =20,600

For the second year

P=20,600

R=10%

T=1yr

P*r*t/100

= 20600*10*1/100

=Ci = 2060

After 2nd year he returns 1660

20600+2060-1660

=21000

So outstanding amount at the beginning of the 3rd year will be Rs. 21000

Answer 2

Here is your answer

Balance is 21000