Question

Mr. Ram wants to put tiles of length 10cm and breadth 9cm to his room having lenth 120cm and breadth 90cm how many tiles are reqd to covered the area of his room ?​

Answer 1

Answer:

To Find:- number of tiles required

Solution:-

First of all

Find area of the room floor and tiles

both are rectangular figures,as they have length amd breadth

Area of the room= L×B

Area=120×90

Area=10,800cm²

Area of 1 tile= L×B

Area = 10×9

Area= 90cm²

And now to find number of tiles required

10,800÷90=120 tiles

therefore the required number of tiles= 120

Answer 2

Answer:

the length of tile = 10 cm

the breadth of tile = 9 cm

area of tile =

$length \: of \: tile\times \: breadth \: of \: tile$

= 10 cm x 9 cm

=

${90 \: cm}^{2}$

the length of room = 120 cm

the breadth of room = 90 cm

area of room = length of room x breadth of room

= 120 cm x 90 cm

=

${10800 \: cm}^{2}$

no. of tiles required =

$\frac{area \: of \: room}{area \: of \: tile}$

=

$\frac{10800 {cm}^{2} }{90 {cm}^{2} }$

=

$120 {cm}^{2}$