mr. ravi has a recurring deposit account of 400 pr month at 10% per annum. if he gets 16220. at the time of maturity, find the total time for which the account was held.
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the account was held for approximately 13 years.
Step-by-step explanation:
Ravi deposits 400 per month.
In one year, he will have deposited (400 × 12) = 4800
So, after one year Ravi will have deposited 4800.
The amount earns interest of 10% per annum.
The compound interest accumulation formula is given by:
A = P(1 + i)ⁿ
In this case:
P = 4800
i = 10%
A = 16220
Doing the substitution we have:
16220 = 4800(1.1)ⁿ
16220/4800 = (1.1)ⁿ
3.37917 = 1.1ⁿ
Taking logs on both sides we have:
log 3.37917 = n log 1.1
0.52881 = 0.041393n
n = 0.52881/0.041393
n = 12.77 approximately 13 years.
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