Question

Mr RK near get Rupees 6455 at end of one year at the rate of 14% annual in a recurring deposit account find the money installment​

Answer 1

Step-by-step explanation:

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Answer 2

I hope this is helpful for you

MaturityAmount(MA)=Rs6455

<br/>Numberofmonths(timeorn)=1×12months=12months

<br/>Rate(r)=14%

\bold{ We \: Know, Maturity \: Amount =Pn + Interest}WeKnow,MaturityAmount=Pn+Interest

Hence,

\begin{gathered} \bold{ 6455 = (12 \times P) + \frac{P \times n \times (n + 1)}{2 \times 24} \times \: \frac{14}{100} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (Interest \: = \frac{P\times n \times (n + 1)}{2 \times 24} \times \frac{r}{100} ) \\ \\ \\ = > 6455 = 12 P + \frac{13P \times 7}{100} \\ \\ \\ = > 6455 = \frac{1200P + 91P}{100} \\ \\ \\ = > \frac{6455 \times 100}{1291} = P \\ \\ \\ = > 500 = P\end{gathered}

6455=(12×P)+

2×24

P×n×(n+1)

×

100

14

(Interest=

2×24

P×n×(n+1)

×

100

r

)

=>6455=12P+

100

13P×7

=>6455=

100

1200P+91P

=>

1291

6455×100

=P

=>500=P

Hence, P = ₹500

\mathbf{P = Principal = Monthly \: Instalment = Rs500}P=Principal=MonthlyInstalment=Rs500

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