Math, asked by sudiptasen3182, 1 month ago

Mr. Rohit borrowed 26400 from a Bank to buy a scooter at a rate of 15% p.a. compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan?

a/Rupees 36649.70
b/Rupees 36759.60
c/Rupees 36659.80
d/Rupees 36659.70


plz anyone give me the correct answer and if you don't know the answer leave it and plz if anyone know the answer plz give me it's urgent​

Answers

Answered by llitzUrLovell
2

Answer:

Correct option is

A

36660

Principal (P) = Rs26,400

Rate (R) = 15% per annum

Number of years (n) = 2

12

4

The amount for 2 years and 4 months can be calculated by first calculating the amount for 2 years using the compound interest formula, and then calculating the simple interest for 4 months on the amount obtained at the end of 2 years.

For calculating amount of first 2 years,

Amount = Principal(1+

100

R

)

Time

Interest = Amount - Principal

Amount = 26400(1+

100

15

)

2

Amount=34914

Now, the interest for next

3

1

years will be calculated using Simple Interest

S.I. =

100

(P×R×T)

S.I. =

100

34914×15×

3

1

S.I. = 1745.70

Therefore, total amount to be paid after 2 years and 4 months = 34,914+1,745.70=Rs 36,659.70

Nearest whole number to 36659.70 is 36660.

Correct  \: option \:  is \: </p><p>A \: </p><p> \: 36660</p><p> \: Principal \:  (P)  \: =  \:  \:  \:  \: Rs26,400</p><p>Rate  \:  \: (R) \:  = 15% per  \: annum</p><p>  \: Number  \: of  \: years \:  (n)  \: = 2 </p><p>12</p><p>4</p><p>	</p><p> </p><p></p><p>The \:  amount  \: for  \: 2  \: years \:  and  \: 4  \: months \:  can \:  be \:  calculated  \: by \:  first \:  calculating the \:  amount \:  for \:  2  \: years \:  using  \: the  \: compound  \: interest \:  formula, \:  and  \: then \:  calculating \:  the  \: simple \:  interest \:  for \:  \:  \:  \:  4 \:  months \:  on \:  the \:  amount \:  obtained  \: at \:  the  \: end \:  of 2 \:  \:  years.</p><p>For  \: calculating \:  amount  \: of \:  first \:  2 years,</p><p></p><p>Amount \:  = Principal(1+ </p><p>100</p><p>R</p><p>	</p><p> ) </p><p>Time</p><p> </p><p>Interest = Amount - Principal</p><p></p><p>Amount = 26400(1+ </p><p>100</p><p>15</p><p>	</p><p> ) </p><p>2</p><p> </p><p>Amount=34914</p><p></p><p>Now, the interest for next  </p><p>3</p><p>1</p><p>	</p><p>  years  \: will \:  be \:  calculated \:  using \:  Simple  \: Interest</p><p>S.I. =  </p><p>100</p><p>(P×R×T)</p><p>	</p><p> </p><p>S.I. =  </p><p>100</p><p>34914×15× </p><p>3</p><p>1</p><p>	</p><p> </p><p>	</p><p> </p><p>S.I. = 1745.70</p><p></p><p>Therefore, \:  total  \: amount \:  to \:  be  \: paid  \: after  \: 2 years \:  and  \: 4  \: months \:  = 34,914+1,745.70=Rs 36,659.70</p><p>Nearest  \: whole \:  number  \: to 36659.70  \: is 36660.</p><p>

Step-by-step explanation:

\huge\mathfrak\pink{Itz \: Ur \:  Lovee}

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