Question

Mr's. pinto is three times her sons age. after four years she will br 22yrs elder to her son. finf the present ages of Mrs pinto anf her son.

Answer 1

Let the age of son be X years. 
Let age of Mrs. Pinto be Y years.

Therefore current age of Mrs. pinto, Y  = 3X. ----- eqn 1.

AFTER 4 YEARS.
Y+4 = X+22. ----- eqn 2.

So, from 1st equation we have Y=3X
and from 2nd equation we have Y+4 = X+22. 

Put value of Y from equation 1 in equation 2,
(3X)+4=X+22
3X-X=22-4
2X=18
X=9 (This is the current age of son)

Again, from equation 1 we had,
Y=3X
Therefore, Y=3x9 = 27 yrs.
Therefore,

Current age of son = 9yrs.
Current age of Mrs. Pinto= 27yrs. 


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Answer 2

Concept Introduction:

Age after n years = $X + nX + n$.

Age n years ago = $X$– $n$.

n times the present age =$nX.$

If ages in the numerical are mentioned in the ratio $A:B$, then $A:B$ will be $AX$ and $BX$.

Given:

Mrs pinto is three times her sons age. after four years she will be $22$ yrs elder to her son.

To Find:

Find the present ages of Mrs pinto and her son.

Solution:

According to question:

Let the age of son be $X$ years.

Let age of Mrs. Pinto be$Y$ years.

Therefore current age of Mrs. pinto, $Y = 3X$. ----- eqn 1.

AFTER $4$ YEARS.

$Y+4 = X+22.$ ----- eqn 2.

So, from 1st equation we have$Y=3X$

and from 2nd equation we have $Y+4 = X+22.$

Put value of $Y$ from equation$1$ in equation$2$,

$(3X)+4=X+22$

$3X-X=22-4$

$2X=18$

$X=9$ (This is the current age of son)

Again, from equation $1$ we had,

$Y=3X$

Therefore, $Y$=$3$x$9$ = $27$ yrs.

Final Answer:

Current age of son = $9$ yrs.

Current age of Mrs. Pinto=$27$ yrs.

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