Mr sarvagya 1/3 of his money to Sonal and 5.12.2 Kunal ki deposit the rest of the money equal in three accounts what fraction of his money did he deposit in SBI account
Answers
Given:
A wooden block of mass 400 gram float vertically in a liquid of density 0.8 gram/cm cube. The volume of the block is 625 cm³.
To find:
Volume of block above liquid surface ?
Calculation:
In case of floating, the weight of the block is being balanced by the buoyant force:
\therefore \: F_{b} = mg∴F
b
=mg
\implies \: (V_{inside}) \rho g = (V_{total}) \sigma g⟹(V
inside
)ρg=(V
total
)σg
\implies \: \dfrac{V_{inside}}{V_{total}} = \dfrac{ \sigma}{ \rho}⟹
V
total
V
inside
=
ρ
σ
\implies \: \dfrac{V_{inside}}{625} = \dfrac{ (\frac{400}{625} )}{ 0.8}⟹
625
V
inside
=
0.8
(
625
400
)
\implies \: \dfrac{V_{inside}}{625} = \dfrac{ 0.64}{ 0.8}⟹
625
V
inside
=
0.8
0.64
\implies \: \dfrac{V_{inside}}{625} = 0.8⟹
625
V
inside
=0.8
\implies \: V_{inside} = 500 \: {cm}^{3}⟹V
inside
=500cm
3
\implies \: V_{outside} =(625 - 500 )\: {cm}^{3}⟹V
outside
=(625−500)cm
3
\implies \: V_{outside} =125 \: {cm}^{3}⟹V
outside
=125cm
3
So, volume outside liquid is 125 cm³.