Math, asked by Gurrie1020, 1 month ago

Mr. Satya Travel with bike at 30 km/hr. and reaches his college 7 minutes late. Next day he travel with bike at 36>km/hr. and start at the same time, reaches his school 10 min early. How far is the school from his house?​

Answers

Answered by RvChaudharY50
0

Given :- Mr. Satya Travel with bike at 30 km/hr. and reaches his college 7 minutes late. Next day he travel with bike at 36 km/hr. and start at the same time, reaches his school 10 min early.

To Find :- How far is the school from his house ?

Answer :-

  • Distance = [(S1 * S2)/(S2 - S1)] * (Time difference / 60)

given that,

  • S1 = 30 km/h .
  • S2 = 36 km/h .
  • Time difference = 7 min late + 10 min early = 17 minutes .

putting all values we get,

→ D = (30 * 36)/(36 - 30) * (17/60)

→ D = (30 * 36/6) * (17/60)

→ D = 180 * (17/60)

→ D = 51 km (Ans.)

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