Mr. Satya Travel with bike at 30 km/hr. and reaches his college 7 minutes late. Next day he travel with bike at 36>km/hr. and start at the same time, reaches his school 10 min early. How far is the school from his house?
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Given :- Mr. Satya Travel with bike at 30 km/hr. and reaches his college 7 minutes late. Next day he travel with bike at 36 km/hr. and start at the same time, reaches his school 10 min early.
To Find :- How far is the school from his house ?
Answer :-
- Distance = [(S1 * S2)/(S2 - S1)] * (Time difference / 60)
given that,
- S1 = 30 km/h .
- S2 = 36 km/h .
- Time difference = 7 min late + 10 min early = 17 minutes .
putting all values we get,
→ D = (30 * 36)/(36 - 30) * (17/60)
→ D = (30 * 36/6) * (17/60)
→ D = 180 * (17/60)
→ D = 51 km (Ans.)
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