Question

mr saxena is 24 year older than his son, vinay. after 2 years , the age of mr saxena will be 3 times that of vinay. find their present ages​

Answer 1

Answer:

$\boxed{\text{\bf The present age of Vinay = 10 years }} \\ \boxed{\text{\bf The present age of Mr.Saxena =10+24 = 34 years}}}$

Step-by-step explanation:

$\boxed{\textbf{Given,}}$

=> Mr.Saxena is 24 year older than his son,Vinay.

=> After 2 years , the age of Mr.Saxena will be 3 times that of Vinay.

$\boxed{\textbf{Present ages :}}$

=> Let the present age of Vinay be x years

=> Then the present age of Mr.Saxena = (x + 24) years

$\boxed{\textbf{After 2 years,}}$

=> Vinay's age = (x + 2) years

=> Mr.Saxena's age = (x + 24 + 2) = (x + 26) years

according to the question,

(x + 26) = 3(x + 2)

x + 26 = 3x + 6

3x - x = 26 - 6

2x = 20

x = 20/2

$\boxed{\textbf{x = 10}}$

$\boxed{\text{\bf The present age of Vinay = 10 years }} \\ \boxed{\text{\bf The present age of Mr.Saxena =10+24 = 34 years}}}$

Answer 2

Answer:

Vinay = 10 years old

Mr.Saxena = 34 years old

Step-by-step explanation:

Let Vinay's present age be x

then, Mr.Saxena's present age will be x + 24

Now, after 2 years

Vinay's age will be x + 2

Mr.Saxena's age will be x + 24 + 2 = x + 26

According to the Question,

x + 26 = 3(x + 2)

x + 26 = 3x + 6

3x - x = 26 - 6

2x = 20

x = 20/2 = 10

So, Vinay's present age is 10 years and Mr.Saxena's present age is 10 + 24 = 34 years

Hope it helped and you understood it........All the best