Mr. Sharma borrowed some money from a friend at the interest rate of 8% per annum. He repaid his debt by paying rs 16,800 at the end of 5 years. How much did he borrow?
Answers
Answered by
34
Abbreviations used throughout the answer:
1. Amount = A
2. Simple Interest = SI
3. Rate of interest = R
4. Time = T
5. Principal = P
Answer:
Unless mentioned the principal is said to be calculated at simple interest.
Let the principal be ₹ P.
Given,
R = 8 % p.a.
T = 5 years
We know,
Simple Interest = (PRT) / 100
SI = (P * 8 * 5) / 100
SI = 40P / 100
SI = 4P / 10
Amount = P + SI
A = P + 4P/10
A = 14P/100
But according to question,
A = ₹ 16800
14P/100 = 16800
P = 1680000/14
P = ₹ 120000
Hence,
The principal or the sum borrowed was ₹ 1,20,000
1. Amount = A
2. Simple Interest = SI
3. Rate of interest = R
4. Time = T
5. Principal = P
Answer:
Unless mentioned the principal is said to be calculated at simple interest.
Let the principal be ₹ P.
Given,
R = 8 % p.a.
T = 5 years
We know,
Simple Interest = (PRT) / 100
SI = (P * 8 * 5) / 100
SI = 40P / 100
SI = 4P / 10
Amount = P + SI
A = P + 4P/10
A = 14P/100
But according to question,
A = ₹ 16800
14P/100 = 16800
P = 1680000/14
P = ₹ 120000
Hence,
The principal or the sum borrowed was ₹ 1,20,000
Answered by
19
Answer:
$ 12000
Step-by-step explanation:
Given,
R =8 % per annum
A = $16800
T = 5 years
S.I = p*R*T /100
= x *8*5/100 = 2x/5
amount =P + si
16800= x + 2x/5
16800 = 7x/5
x = $( 5*16800/100) = 5*2400
then, x = $ 1200.
thank you for this question
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