Question

Mr. Sharma gave 1/3 of his money to Sonal and

5/12 of the money to Kunal. He deposited the rest of the

money equally in 3 accounts. What fraction of his money did he deposit in each account?​

Answer 1

Answer:

answer:

54

step-by-step explanation:

let the number be x

then,1/3 of 1/4 of x=15

x=15*3*4=180

so required number =((3/10)*180)=54

Answer 2

Answer:

The fraction of his money Mr. Sharma gave to:

Sonal → \frac{1}{3}

3

1

of his money

Kunal → \frac{5}{12}

12

5

of his money

Mr. Sharma deposited rest of the money equally into 3 of his accounts

To find:

The fraction of his money he deposited in each account

Solution:

Let Mr. Sharma initially has "x" money with him.

So, he gave to

Sonal → \frac{x}{3}

3

x

Kunal → \frac{5x}{12}

12

5x

∴ Total amount Mr. Sharma gave from his money = \frac{x}{3} + \frac{5x}{12}

3

x

+

12

5x

= \frac{4x \:+\: 5x}{12}

12

4x+5x

= \frac{9x}{12}

12

9x

After giving to Sonal and Kunal, Mr. sharma is left with,

= x - \frac{9x}{12}x−

12

9x

= \frac{12x\:-\:9x}{12}

12

12x−9x

= \frac{3x}{12}

12

3x

= \frac{x}{4}

4

x

Since this rest of his money after giving to Sonal and Kunal i.e., \frac{x}{4}

4

x

, Mr. Sharma had divided equally into 3 of his accounts. So, each account will have \frac{1}{3}

3

1

rd of the rest of the money he was left with.

∴ The fraction of his money in each accounts is,

= \frac{1}{3} \:\times\:\frac{x}{4}

3

1

×

4

x

= \frac{x}{12}

12

x

= \bold{\frac{1}{12}}

12

1

of his money

Thus, Mr. Sharma deposited \underline{\frac{1}{12}}

12

1

of his money in each of the 3 accounts. plz mark me brainliest