Question

Mr. Sharma gave 1/3 of his money to sonal and 5/12 of the money to kunal.He deposited the rest of the money equally in 3 accounts. What fraction of his money did he deposited in each account?

Answer 1

Given:

The fraction of his money Mr. Sharma gave to:

Sonal → $\frac{1}{3}$ of his money

Kunal → $\frac{5}{12}$ of his money

Mr. Sharma deposited rest of the money equally into 3 of his accounts

To find:

The fraction of his money he deposited in each account

Solution:

Let Mr. Sharma initially has "x" money with him.

So, he gave to

Sonal → $\frac{x}{3}$

Kunal → $\frac{5x}{12}$

∴ Total amount Mr. Sharma gave from his money = $\frac{x}{3} + \frac{5x}{12}$ = $\frac{4x \:+\: 5x}{12}$ = $\frac{9x}{12}$

After giving to Sonal and Kunal, Mr. sharma is left with,

= $x - \frac{9x}{12}$

= $\frac{12x\:-\:9x}{12}$

= $\frac{3x}{12}$

= $\frac{x}{4}$

Since this rest of his money after giving to Sonal and Kunal i.e., $\frac{x}{4}$, Mr. Sharma had divided equally into 3 of his accounts. So, each account will have $\frac{1}{3}$rd of the rest of the money he was left with.

∴ The fraction of his money in each accounts is,

= $\frac{1}{3} \:\times\:\frac{x}{4}$

= $\frac{x}{12}$

= $\bold{\frac{1}{12}}$ of his money

Thus, Mr. Sharma deposited $\underline{\frac{1}{12}}$ of his money in each of the 3 accounts.

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Answer 2

Answer:

1/12

Step-by-step explanation:

Let Mr. Sharma money be = x

Sonal=x/3

Kunal=5x/12

Total amount :

x/3+5x/12

=4x+5x/12

=9x/12

Then,

x-9x/12

=12x-9x/12

=3x/12

=x/4

Then,

1/3×x/4

=x/12

=1/12 of x

So 1/12 is the answer .