Mr. Sharma lends ₹24000 at 13% p.a simple interest and an equal sum at 12% p.a compound interest. Find the total interest earned by Mr. Sharma in 2 years.
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Principal=Rs24000
rate of interest=13%p.a
No. of years=2 years
simple interest=PNR/100
=24000×13×2/100
=6240
so simple interest=Rs6240
Principal=Rs24000
Rate of interest=12%p.a
No. of year=2
Amount=p[1+R/100]ⁿ
=24000×112/100×112/100
=30105.6
compound interest=Amount-Principal
=30105.6-24000
=6105.6
total interest earned=6240+6105.6
=12345.6
rate of interest=13%p.a
No. of years=2 years
simple interest=PNR/100
=24000×13×2/100
=6240
so simple interest=Rs6240
Principal=Rs24000
Rate of interest=12%p.a
No. of year=2
Amount=p[1+R/100]ⁿ
=24000×112/100×112/100
=30105.6
compound interest=Amount-Principal
=30105.6-24000
=6105.6
total interest earned=6240+6105.6
=12345.6
Answered by
2
rs. 12345.6
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