Question

mr Sharma observes that cooking gas cylinder weighs less by 1/3 by 15th of every month. what fraction of gas remains in cylinder for the rest of every month

Answer 1

Answer:

On 15th 1/3 of weight

Remaining 1-1/3=2/3

Answer 2

Answer:

Remaining fraction = $\frac{2}{3}$.

Step-by-step explanation:

In the question,

The observance by Mr. Sharma includes that the weight of the cylinder is reduced by $\frac{1}{3}$ by 15th or half of the month.

Therefore, we need to find out the remaining fraction of the gas in the cylinder for the rest of the month.

So,

For that using the simple fraction, we get,

$1-\frac{1}{3}=Remaining\ fraction\\Remaining\ fraction=\frac{2}{3}$

Therefore, the rest of the month we are left with only $\frac{2}{3}$ fraction of the gas in the cylinder.

Hence, the remaining fraction is $\frac{2}{3}$.