Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed? y – 12 = –5(x + 2) y – 12 = 2(x + 2) y + 12 = 2(x – 2) y + 12 = –5(x – 2)
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Step-by-step explanation:
F(x) = -5x + 2, let f(x) = y
y = -5x + 2. Comparing to y = mx + c, the slope m = -5,
The point (-2, 12) is the (x₁, y₁)
The point slope form is :
y - y₁ = m(x - x₁), slope m = -5
y - 12 = -5(x - -2)
y - 12 = -5(x + 12)
f(x) - 12 = -5(x + 12) is the point - slope form.
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