Question

mr sinha borrowed rs 4575 on 1st july, 2010 and returned the amount on 31st December 2010. if the rate of interest was 9%, what amount did he return ?​

Answer 1

He returned Rs. 4780.88

Step-by-step explanation:

Mr. Sinha borrowed money on 1st July 2010  = Rs. 4575

He returned amount on 31st December 2010.

Rate of interest = 9%

Time duration from 1st july 2010 to 31st December 2010 = 6 months

We will use simple interest formula :

$I=\frac{p\times r\times t}{100}$

Where,  I =  Interest amount

P = principal amount = 4575 Rs.

r = rate of interest = 9% or 9/100

t = time in years = 0.5

Now put the values into the formula :

$=\frac{4575\times 9\times 0.5}{100}$

= $\frac{20587.5}{100}$

= 205.875

≈ 205.88

Amount = Principal + interest

             = 4575 + 205.88

             = 4780.88

He returned Rs. 4780.88

Learn more simple interest : https://brainly.in/question/14878973