Math, asked by bajanadebnath20, 8 months ago

Mr. Sinha sold two tape-recorders for 990
each; gaining 10% on one and losing 10% on
the other. Find his total loss or gain, as
percent, on the whole transaction​

Answers

Answered by ramsuratawasthi79
7

Answer:

SP of both tape recorders: 1980Rs.

let the CP be x

CP for 1st tape recorder

x+1/10x=990

11x/10 = 990

x=900 Rs.

CP for 2nd tape recorder

x-1/10x =990

9x/10 = 990

x = 1100

therefore total CP= 2000Rs.

hence there is a loss of 20 Rs.

so, overall he has loss of 1%.

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Answered by nakulgoel38
3

Sp=990

P=10%

Cp=sp×100/100+p%

=990×100/100+10

990×100/110=900

2nd sp=990

L=10%

2nd cp=2nd sp×100/100-L%

990×100/100-10 = 1100

2nd cp=1100

Total sp=990+990=1980

Total cp=900+1100=2000

L=cp-sp

L=2000-1980=20

L=20

L%=1×100/cp

20×100/2000=1

L%=1%

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