Question

Mr. Sunil bought a certain number of shirts for Rs. 750, each shirt costing the same, he sold each shirt at Rs.

42 with the total sales proceeds he could buy 10 more shirts than before. How many shirts did he buy

originally.​

Answer 1

Given :

Mr. Sunil bought shirts for 750 Rs. and sold each shirt for Rs. 42.00.

To Find :

The amount of shirts he bought.

Solution :

Let the number of shirts bought by Mr. Sunil = x

Total price of x shirts = 750

The price for one shirt = $\frac{750}{x}$

Each shirt sold for Rs. 42.

Selling price of shirts = 42x

Profit = selling price - cost price

Profit = 42x - 750

With this profit Sunil purchased 10 more shirts than before. So the equation will be

$10\times \frac{750}{x}$ = 42x - 750

42x² - 750x - 7500 = 0

7x² - 125x - 1250 = 0

7x² - 175x + 50x - 1250 = 0

7x( x - 25 ) + 50 (x - 25) = 0

(7x + 50) (x - 25) = 0

x = 25, $-\frac{50}{7}$

But x can not be a negative value.

Therefore, number of shirts purchased = 25