Mr Suresh has a Recurring Deposit Account of 300 per month.If the rate of interest is
12% and the maturity value of this account is 8,100 ;find the time (in years)of this
Recurring Deposit Account
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Answer:
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Step-by-step explanation:
Correct option is
A
2
P=300 per month , R=12% , MV=1800
Maturity Value =(1+
2400
(n+1)×R
)×n×P
where n is the time in months.
⟹8100=(1+
2400
(n+1)×12
)×n×(300)
⟹27=n+
200
(n
2
+n)
⟹n
2
+201n−5400=0
⟹(n−24)(n+225)=0
⟹n
=−225
∴n=24 months =2 years
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