Question

Mr. Suzuki, a car dealer, sold cars of only two brands, A and B, in the previous year. This year, he introduced a

new brand, C. The number of cars of brand A and brand B sold in the previous year were in the ratio 3:2, and

the ratio of the number of cars sold in the previous year to that sold in this year is 2:3 for brand A and 2:5 for

brand B. Further, the number of cars of brand C sold this year forms 81% of the total number of cars sold this

year.

Find the number of cars of brand C sold this year, given that a total of 24 cars of brand A were sold in the

previous year​

Answer 1

Answer:

324

Step-by-step explanation:

the no of car A sold in previous year = 24

the ratio of A and B in the previous year = 3:2

let, 3x be A and 2x be B.

∴ 3x = 24,   x = 8

∴ B = 2 x 8 = 16

cars of brand A sold previous year : this year =  2 : 3 or 2y (prev yr) and 3y (this yr)

now, 2y = 24 ; y = 12 and 3y = 3 x 12 = 36

cars of brand B sold previous yr : this yr = 2 : 5 or 2k (prev yr) and 3k (this yr)

now, 2k = 16; k = 8 and 5k = 5 x 8 = 40

∴ total no of A + B sold this year = 36 + 40 = 76

now cars of C sold this year = 81 %

if A+B+C = 100% then A+B = 100% - 81% = 19%

now, 19 % = 76  ( total no of cars of brands A+B)

or,        1 % = 4  ∴ 81% = 81 x 4 = 324 (no of cars of brand C)

Answer 2

Answer:

the answer is 324

Step-by-step explanation: