..Mr. Thomas invested an amount
of Rs. 13,900 divided in two dif-
ferent schemes A and B at the
simple interest rate of 14% p.a.
and 11% p.a. respectively. If the
total amount of simple interest
earned in 2 years be Rs. 3508,
what was the amount invested
in Scheme B? (in Rs.)
Answers
Answer:
Let the investment in scheme A be Rs.x
and the investment in scheme B be Rs.(13900−x)
We know that SI=
100
P×R×T
Simple Interest for Rs.x in 2 years at 14% p.a =
100
x×14×2
=
100
28x
Simple Interest for Rs.(13900−x) in 2 years at 11% p.a.=
100
(13900−x)×11×2
=
100
22(13900−x)
Total interest=Rs.3508
⇒
100
28x
+
100
22(13900−x)
=3508
⇒28x+305800−22x=350800
⇒6x=45000⇒x=
6
45000
⇒x=7500
Investment in Scheme B =13900−7500=6400Rs
Explanation:
Given : Invested Amount Rs 13900 divided in 2 different schemes A and B at SI 14% pa and 11% pa
Total amount of SI earned in 2years = 3058
To Find : Amount invested in Scheme B
Solution:
Let say Amount invested in Scheme B = 100P
Amount invested in Scheme A = 13900 - 100P
= 100(139 - P)
SI = P x R x T /100
invested in Scheme A =100(139 - P)
R = 14%
T = 2
SI = 100(139 - P) * 14 * 2 /100
= (139 - P)28
= 3892 - 28P
invested in Scheme B =100P
R = 11%
T = 2
SI = 100P * 11 * 2 /100
=22P
3892 - 28P + 22P = 3508
=> 3892 - 6P = 3508
=> 6P = 384
=> P = 64
=> 100P = 6400
Amount invested in Scheme B = Rs 6400