Mr. x drives to his office at an average speed of 48 km per hour. The time taken to
cover the first 60% of the distance is 10 minutes more than the time taken to cover the
remaining distance. How far is his office?
Answers
Answer:
Let the total distance be xkm.
Time taken to cover remaining 40% of x distance T
1
=
100×48
40×x
But given time taken to cover first 60% of x distance is T
2
=T
1
+
60
10
hrs
⇒ T
2
=
100×48
60×x
∴
100×48
60×x
=
100×48
40×x
+
60
10
⇒
100×48
60×x
−
100×48
40×x
=
60
10
⇒
4800
20x
=
60
10
⇒ x=
60
10
×
20
4800
⇒ x=40km
Answer:
⇒ x=40km
Step-by-step explanation:
Let the total distance be xkm.
Time taken to cover remaining 40% of x distance T
1
=
100×48
40×x
But given time taken to cover first 60% of x distance is T
2
=T
1
+
60
10
hrs
⇒ T
2
=
100×48
60×x
∴
100×48
60×x
=
100×48
40×x
+
60
10
⇒
100×48
60×x
−
100×48
40×x
=
60
10
⇒
4800
20x
=
60
10
⇒ x=
60
10
×
20
4800
⇒ x=40km