Question

Mr. X is a book worm and his wife Mrs. Y is also a voracious reader. x reads at an average rate of 40 pages per
hour, while Y reads at an average rate of 50 pages per hour. X starts reading a novel at 4.30 pm and Y begins
reading an identical copy of the same book at 5.20 pm. At 6.00 pm suddenly a family friend arrived and both
husband and wife had to spend 30 minutes with the guest. Thereafter, they started reading again. At what time
will both husband and wife will be reading the same page?
(a) 10.00 pm
(b) 9.30 pm
(C) 9.10 pm
(d) 8.20 pm​

Answer 1

Answer:

(c) 9:10 pm

Step-by-step explanation:

Rate of X = 40 pages/hour

Rate of Y = 50 pages/hour

In  1 and 1/2 hour (4:30-6:00pm) , X will read = 40 * 3/2 = 60 pages

In 40 minutes (5;20 - 6:00pm) Y will read = 50* 2/3 = 100/3 pages

They again start reading and 6:30 pm

Difference at 6:30 pm = 60 - 100/3 = 80/3 pages .

X is ahead by 80/3 pages.

In one hour X reads 10 page less than Y

In 1/3 hour (20 minutes)  X will read 10/3 pages less than Y.

So for 80/3 pages , time required = 20*8= 160 minutes = 2 Hour 40 Minutes

X and Y will be reading the same page at 6:30+ 2 Hour 40 Minutes

= 9:10 pm