Question

Mr.X lent 600 to Mr Y for 2 years and 150 to Mr.Z for 4 years.He received 90 as interest from both of them .Find the rate of interest he charged from them

Answer 1

Let the sum borrowed be Z. Then,

(Zx6x2⁄100) + (Zx9x3⁄100) + (Zx14x4⁄100) = 11400

Therefore, 3Z⁄25 + 27Z⁄100 + 14Z⁄25) = 11400

? 95Z⁄100 = 11400

Z = (11400x100⁄95) = 12000

Answer 2

hey mate the answer is

Let the number be n

(n×6×2/100)+ (n×9×2/100)+ (n×14×4/100)=11400

so 3n/25 + 27n/100+ 14n/25=11400

95n/100=11400

n=11400×100/95=12000

n=12000

hope it might help you