Question

mr x lent rs 1000 at 10/ p.a for 3 year at compound interest find the mount and compound interest​

Answer 1

SOLUTION:-

Given,

⚫P= Rs.1000

⚫R= 10% p.a.

⚫T= 3 years

We know that Formula of Compound Interest;

$A = P(1 + \frac{R}{100} ) {}^{n}$

Therefore,

$A= 1000(1 + \frac{10}{100} ) {}^{3} \\ \\ = > 1000(1 + \frac{1}{10} ) {}^{3} \\ \\ = > 1000( \frac{10 + 1}{10} ) {}^{3} \\ \\ = > 1000( \frac{11}{10} ) {}^{3} \\ \\ = > 1000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} \\ \\ = > ( { 11) }^{3} \\ \\ = >Rs.1331$

Now,

C.I.= A-P

C.I.= Rs.1331 - Rs.1000

C.I.= Rs.331

Hope it helps ☺️