Question

Mr.Ziah is 10 years more than twice the age of his son. The sum of their ages is 55. Solve for their ages

Answer 1

Answer:

son = 15

Mr.Ziah = 40

Step-by-step explanation:

let son be of x years old

mr.ziah = 2x+10

x+2x+10 =55

3x +10= 55

3x = 55-10

3x = 45

x = 45/3

x = 15

2x+10 = 2*15+10

= 40