mrs arora open a recurring deposit account in a bank and deposited rupees 1500 per month for 3 years if he got rupees 6660 as interest the rate of interest was
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Answer:
S.I. = P ×
2×12
n(n+1)
×
100
r
=1,200×
2×12
36(36+1)
×
100
10
=1,200×
24
1332
×
100
10
S.I = Rs 6,660
Hence,
The amount that A will be getting at the time of maturity is
=Rs(1,200×36)+Rs6,660
=Rs43,200+Rs6,660
=Rs49,860
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