Math, asked by pinkukumarpatna800, 2 months ago

Mrs.Boss is 5 times as old as his son.Six years later he will be three times as old as his son .Find the present age of Mr. Boss.​

Answers

Answered by Anonymous
0

Answer:F, S={90 years old, 18 years old}

PREMISES

5S+6=4(S+6)

ASSUMPTIONS

Let F=the father's age (5S)

Let S=the son's age (S)

Let the father's age in 6 years=5S+6

Let the son's age in 6 years=S+6

CALCULATIONS

5S+6=4(S+6)

5S+6=4S+24

(5S-4S)+6=(4S-4S)+24

S+6=0+24

S+(6–6)=24–6

S+0=18

S=

18 years old

and,

if F=5S, then

F=5(18)

F=

90 years old

PROOF

If F, S=90,18 years old respectively, then the equations

5S+6=4(S+6)

5(18)+6=4(18+6)

90+6=72+24 and

96 years old=96 years old prove the roots (zeros) F, S={90, 18 years old respectively} of the statement 5S+6=4(S+6)

Step-by-step explanation:

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