Math, asked by kanishkyadav0219, 9 months ago

Mrs jain is 27 years older than her daughter nilu. After 8 years she will be as twice as nilu. Find their present ages

Answers

Answered by avikatyagi2020
6

Let Nilu's age be x years.

So, her mother's age= x+27 years.

ATQ (According to question),

x+27+8=2 (x+8)

2x+16=x+35

x=19

So, Nilu's age = x = 19 years.

And her mother's age= 19 +27= 46 years.

Hope it helps... please mark as brainliest☺☺

Answered by lalrintluangitei19
0

Answer:

nilu=19

mrs.jain=46

Step-by-step explanation:

jain=x+27

daughter=x

after 8 yrs

jain=x+27+8

daughter=x+8

we have

x+27+8=2(x+8)

x+27+8=2x+16

x-2x=16-8-27

-x= -19

x=19

nilu=19

mrs.jain=46

Similar questions