Math, asked by Radhey03, 3 months ago

Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​

Answers

Answered by Anonymous
82

Given : Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.

To Find : Their present ages.

⠀⠀⠀⠀⠀__________________________

❍Let the present age of Nilu be "x" years.

Therefore,the present age of Nilu's mother = (x + 27) years.

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{\underline{\boldsymbol{\pink{According \ to \ the \ question \ :}}}}

So,after 8 years,

Nilu's age = (x + 8),and Mrs Jain's age = (x + 27 + 8) = (x + 35)years.

 :\implies{ \sf{\pink{x + 35 = 2(x + 8)}}}

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Expanding the brackets,We get

 :\implies{ \sf{\pink{x + 35 = 2x + 16}}}

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Transporing x to RHS and 16 to LHS,We get

 :\implies{ \sf{\pink{35-16=2x-x}}}

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 :\implies{ \sf{\pink{x=19}}}

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So,The present age of Nilu = x = 19 years.And the present age of Nilu's mother that is Mrs Jain = x + 27 = 19 + 27 = 46 years.

Answered by Anonymous
3

answer

Step-by-step explanation:

ǫsɪɴ :

Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?

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ʀǫɪʀ sʟɪɴ :

Daughter Age = x

Neelu's Age = 27 + x

After 8 Years,

Daughter Age = x + 8

Neelu's Age = 27+8+x

= 35 + x

2( x + 8) = 35 + x

2x + 16 = 35 + x

2x - x = 35 - 16

x = 19

Daughter present age = 19 Years

Neelu's Present Age = 27+ x

= 27 + 19

= 46 ʏᴇᴀʀs.

ʜʀғʀ, ɴʟ's ʀsɴ ɢ ɪs 46 ʏʀs.

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