Question

Mrs Jain is 27 years older than her daughter Nitu. she will be twice as old as Nitu. find the present age.​

Answer 1

solution

Let daughter age =x

Mr jain age =x+27

After 8yr x+27+8=x+35according to the conditionX+35=2xX=35Mrs jain age =35+27=62yrs

pls follow tannuranna 59 and mee ✌️

Answer 2

Let the present age of Nitu be x years

Therefore the present age of Nitu’s mother = (x + 27) years

So, after 8 years, Nitu’s age = (x + 8)

and Mrs Jain’s age = (x + 27 + 8) = (x + 35) years

⇒ x + 35 = 2(x + 8)

Expanding the brackets, we get

⇒ x + 35 = 2x + 16

Transposing x to RHS and 16 to LHS, we get

⇒ 35 – 16 = 2x – x

⇒ x = 19

So, the present age of Nitu = x = 19 years

And the present age of Nitu’s mother that is Mrs Jain = x+ 27 = 19 + 27

= 46 years

THEREFORE,

Nitu's age = 19 years

Mrs Jain = 46 years