Math, asked by Saby123, 1 year ago

Mrs Kapoor has a certain sum of money to buy fruits. She can buy N mangoes at rupees 1.60 eat and have Rupees 0.80 left out on the way she can buy (N + 10 )applea at rupees 0.70 each and have to be 0.10 left . If Mrs Kapoor buys 3 mangoes and uses the rest of the money to buy apples, then how much money does Mrs Kapoor have for buying fruits.

Answers

Answered by asritadevi2emailcom
254

 \green{ \underline \bold{total \: money \: of \: mango \:  :}}  \\ \tt :  \implies (1 .60) \times n + 0.8 = mango \\ \orange{ \underline \bold{total \: money \: of \: apple :}} \\  \tt :  \implies \: (0.7) \times (n + 10) + 0.10 = apple \\ \blue{ \underline \bold{let \: see :}} \\  \tt :  \implies \: 1.60n + 0.8 = 0.7n + 7 + 0.1 \\ \tt :  \implies0.9 = 6.3 \\ \tt :  \implies \: n = 6.3 \div 0.9 =  \frac{63}{7}  = 7 \\  \\ \red{ \underline \bold{now :}} \\ \tt :  \implies \: m = 1.6 \times 7 + 0.8 = 11.2 + 0.8 \\ \tt :  \implies12rs \: answer

Answered by vkpathak2671
106

Answer:

totalmoneyofmango:

:⟹(1.60)×n+0.8=mango

totalmoneyofapple:

:⟹(0.7)×(n+10)+0.10=apple

letsee:

:⟹1.60n+0.8=0.7n+7+0.1

:⟹0.9=6.3

:⟹n=6.3÷0.9=

7

63

=7

now:

:⟹m=1.6×7+0.8=11.2+0.8

:⟹12rsanswer

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