Mrs Kapoor invested 6000 every year at the beginning of the year at 10% per annum compound interest calculate the amount of a total savings at the end of the third year
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4
P=rs8000,R=10%p.a ,time=3years
A=p(1+R/100)^3
A=8000(1+10/100)^3
A=8000(11/10)^3
A=8000×11/10×11/10×11/10
A=rs10648
C.I.=A-P
C.I.=10648-8000
C.I.=rs2648
A=p(1+R/100)^3
A=8000(1+10/100)^3
A=8000(11/10)^3
A=8000×11/10×11/10×11/10
A=rs10648
C.I.=A-P
C.I.=10648-8000
C.I.=rs2648
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2
that's correct answer
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