Question

mrs. Kapoor invested 6000 rupees every year at the beginning of the first year at 10% per annum ci. calculate amount of total savings at the: 1.beginning of the third year and 2.at the end of second year​

Answer 1

Step-by-step explanation:

(i) For 1st year :

Since, money invested at the beginning of the year = Rs. 6,000

⇒ Principal for 1st year = Rs. 6,000

∴ Interest =Rs.

100

6,000×10×1

=Rs.600

And, amount =Rs.6,000+Rs.600=Rs.6,600

For 2nd year:

Since, Rs. 6,000 is invested again at the beginning of the second year, therefore, for the second year, principal =Rs.6,600+Rs.6,000=Rs.12,600

Interest =Rs.

100

12,600×10×1

=Rs.1,260

And, amount =Rs.12,600+Rs.1,260=Rs.13,860

∴ Amount of her total saving upto the end of the second year =Rs.13,860

(ii) since, Rs. 6,000 is invested again at the beginning of the third year,

∴ Amount of her total saving at the beginning of the third year

=Rs.13,860+Rs.6,000=Rs.19,860 Ans

Answer 2

Answer:

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