Math, asked by divyanshisingh122005, 2 months ago

Mrs. Mamun invests Rs.250 every month for 2 years in a bank and collects Rs.6312.50 at the end of the term. Find the rate of simple interest paid by the bank on this recurring deposit.

Answers

Answered by 12thpáìn
308

Given that

  • Principal(P) for every 2 mount's=Rs.250
  • Time(T) =2 year's
  • Amount(A) = Rs.6312.50

To Find

  • Rate(R) of simple interest paid by the bank.

To Find the Value of Rate we need to find the Simple interest (SI) .

We know that

\\\overline{\underline{\boxed{\begin{gathered}\implies \sf \purple{ SI=Amount- Principal }\end{gathered} }}}\\\\

  • Principal (P) for 1 month= Rs.250
  • Principal (P)for 12mount's=Rs.250×12
  • Principal (P) for 2 year = Rs.3000×2
  • Principal (P) for 2 year = Rs.6000

\\\\ \text{ \bf{Putting the Value of  \gray{principal} and \gray{ amount} in Formula  we get}}

 \sf{SI=6321 - 6000 }

\sf{SI=RS.312 }

Now

  • Simple interest (SI)=Rs.312
  • principal (P)=6000
  • Time=2 year's

We know that

\\\overline{\underline{\boxed{\begin{gathered}\implies \sf \purple{ SI}=  \dfrac{ \purple{Principal×Rate×time}}{ \purple{100}}\end{gathered} }}}\\

\\\\ \sf{→ 312=  \dfrac{ 6000×Rate×2}{100}}

\sf{→Rate =  \dfrac{312 \times 100}{6000 \times 2}  }

\sf{→Rate =  \dfrac{156}{60 }  }

\sf{→Rate =  \dfrac{39}{ 15}  }

\sf{→Rate =  2.6\%  } \\

  • \\\\\text{\pink{2.6\%}  of Rate paid by}\\\text{ the bank on this recurring deposit.}
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