Question

Mrs Razdan wants to use tiles of length 200
and breadth 10 cm to cover the floor of her
balcony shown in the figure. What is the area
of the balcony? How many tiles does she
need to buy (1 sq m = 10,000 sq cm)?​

Answer 1

Step-by-step explanation:

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Area of balcony=Ar(1)+Ar(2)+Ar(3)

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles=

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2 =10

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2 =10 3

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2 =10 3 .

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m 2 Area of one tile=20×10cm 2 ⇒ Number of tiles= 20×10cm 2 20×10 4 cm 2 =10 3 .solution