Math, asked by nicolechenjb, 9 months ago

mrs sanvi cut a ribbon measuring 430 cm into 3 pieces.The first piece was 150 cm
long.The second piece was three times as long as the third piece.How long was the second piece?

Answers

Answered by prashantrohilla32
0

Answer: .210 cm

Step-by-step explanation:

1st piece=150

remaining =430-150=280 cm.

second piece=3*third piece.

280/4=70.

second piece = 210 cm

third piece= 70 cm.

Answered by immugdhavb
0

Mrs. Sanvi cut a ribbon measuring 430 cm into 3 pieces. The first piece was 150 cm  long. The second piece was three times as long as the third piece. How long was the second piece?

Answer:

210 cm = 2nd part

Step-by-step explanation:

A ribbon measuring 430 cm is cut into 3 parts.

1st piece - 150 cm

2nd piece - '3x' cm [second piece is thrice longer than third piece]

3rd piece - 'x' cm  [assumed]

Therefore,

430 = 150 + 3x + x

430 - 150 = 4x

280 = 4x

x = \frac{280}{4}

x = 70 cm

But 70 cm is the length of the 3rd piece because the 3rd piece = x.

70 cm = x = 3rd piece

We are yet to find the value of the 2nd piece.

2nd piece = 3x (and) x = 70 cm

So, 3x = 3 × 70 ⇒ 210 cm

Finally, we can say that 210 cm is the total length of the second piece

P.S. :-

If you want to verify if the calculation is right then the following equation can be used:

430 = 1st piece + 2nd piece + 3rd piece

150 cm + 70 cm + 210 cm

⇒ 430 cm

[please mark it as brainliest]

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