Question

Mrs. Sharma borrowed a loan from Mrs. Gupta at 10% per annum. At the end of 2 years, she paid an amount of rs. 3600 and clears the debt. Find the sum borrowed by Mrs.Sharma.​

Answer 1

Step-by-step explanation:

3600×10=36×10×2=720

100×2

A=P+I=3600+720=4,320

4,320 SUM BORROWED BY MRS.SHARMA

Answer 2

ANSWER

Let the term borrowed by Mr. sharma =x

at 10% per annum for 2 years

Amount =x(1+

100

10

)

2

=

100

121x

he than pays back 19360 Rs

⇒ Money left =

100

121x

−19360

Name with interest in 3rd year at 10% annum.

Amount =(

100

121x

−19360)(

10

11

)=31944

⇒(

100

121x

−19360)(

10

11

)=31944

⇒

100

121x

−19360=

11

31944×10

=29040

⇒

100

121x

=19360+29040=48400

⇒x=

121

48400×100

=40000 Rs

⇒ Sum borrowed =40000 Rs