Mrs.Sharma has one farm of area 1080 sq meters. She is planning to grow 6 vegetables this season and hence has divided her farm into three unequal parts so that she can grow two vegetables on each part. Area of largest part of the farm is 580 sq meters, the area of smallest farm is 180 sq meters. Help her with the problems she is facing mathematically. (8) a) On the largest part she wants to grow potato and onion in the ratio 19:10. Find the area covered by potato and onion separately.
Answers
Answer:
Mrs.Sharma has one farm of area 1080 sq meters. She is planning to grow 6 vegetables this season and hence has divided her farm into three unequal parts so that she can grow two vegetables on each part. Area of largest part of the farm is 580 sq meters, the area of smallest farm is 180 sq meters. Help her with the problems she is facing mathematically. (8) a) On the largest part she wants to grow potato and onion in the ratio 19:10. Find the area covered by potato and onion separately.Mrs.Sharma has one farm of area 1080 sq meters. She is planning to grow 6 vegetables this season and hence has divided her farm into three unequal parts so that she can grow two vegetables on each part. Area of largest part of the farm is 580 sq meters, the area of smallest farm is 180 sq meters. Help her with the problems she is facing mathematically. (8) a) On the largest part she wants to grow potato and onion in the ratio 19:10. Find the area covered by potato and onion separately.
Given : Mrs.Sharma has one farm of area 1080 sq meters.
She is planning to grow 6 vegetables
largest part of the farm is 580 sq meters,
the area of smallest farm is 180 sq meters.
To Find : On the largest part she wants to grow potato and onion in the ratio 19:10. Find the area covered by potato and onion separately.
Solution:
Mrs.Sharma has one farm of area 1080 sq meters.
largest part of the farm is 580 sq meters,
the area of smallest farm is 180 sq meters.
area of Medium part = 1080 - (580 + 180) = 320 sq meters
On the largest part she wants to grow potato and onion in the ratio 19:10.
=> Potato = (19/29) * 580 = 380 sq meters
Onion = (10/29) * 580 = 200 sq meters
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