Mrs. Smith has bolts of material that have lengths of 42, 63, and 105 inches. She needs to cut the fabric into equal length pieces with none left over. What is the greatest length of fabric pieces she can cut?
Answers
Answered by
7
Find the greatest common factor of 42, 63, and 105.
42 = 2×3×7
63 = 3²×7
105 = 3×5×7
GCF = 3×7 = 21
The greatest length is 21 inches.
:::::
2³×3²
2²×3³
GCF = 2²×3² = 36
:::::
81m²x³ = 3⁴m²x³
:::::
n^3^2 = n⁹
GCF of n⁹ and nt⁴ is n.
:::::
60w⁵y³ = 2²×3×5w⁵y³
78wy² = 2×3×13wy²
GCF = 2×3wy² = 6wy²
ans :- 21 inches
hope helps you
42 = 2×3×7
63 = 3²×7
105 = 3×5×7
GCF = 3×7 = 21
The greatest length is 21 inches.
:::::
2³×3²
2²×3³
GCF = 2²×3² = 36
:::::
81m²x³ = 3⁴m²x³
:::::
n^3^2 = n⁹
GCF of n⁹ and nt⁴ is n.
:::::
60w⁵y³ = 2²×3×5w⁵y³
78wy² = 2×3×13wy²
GCF = 2×3wy² = 6wy²
ans :- 21 inches
hope helps you
Answered by
6
he basics and list out the factors and see which ones work for all three... also, the question shows that it is a gcf problem because of the words equal length pieces, and greatest length of fabric pieces and it deals with three separate lengths
42 63 105
1--------------1------------1
2
3--------------3------------3
4 5
6
7--------------7-------------7
14
21------------21-----------21
Therefore, 21 is the answer, because it is the highest factor to work for all three numbers
the ans is 21 inches.
I hope it help you
42 63 105
1--------------1------------1
2
3--------------3------------3
4 5
6
7--------------7-------------7
14
21------------21-----------21
Therefore, 21 is the answer, because it is the highest factor to work for all three numbers
the ans is 21 inches.
I hope it help you
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