ms=b/s+c find the value of b and c
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Step-by-step explanation:
Dimension of a,bt,ct
2
should be equal to x
x=[L]
So, the dimension of bt will be equal to that of 'x'.
bt=[L]
b=
[T]
[L]
b=[LT
−1
]
The dimension of c can be obtained as:
ct
2
=[L]
c=
[T
2
]
[L]
c=[LT
−2
]
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