Math, asked by ronakverma897, 1 year ago

Ms. Deepti Jain invests 11% of her monthly salary ie rs 5236 in fixed deposit. She invests 19% of her monthly salary on Life Insurance Policies, also she invests another 7% of her monthly salary on Mutual funds. What is the total annual amount Invested by Ms. Deepti Jaun if the monthly investment for each month is equal

Answers

Answered by slicergiza
1

Answer:

23,247.84 rupees

Step-by-step explanation:

Given,

Monthly salary = rs 5236,

Investments,

In fixed deposit = 11%,

In Life Insurance Policies = 19%,

In Mutual funds = 7%,

So, total investment = 11% + 19% + 7% = 37%,

Thus, monthly investment = 37% of 5236

=\frac{37\times 5236}{100}

= rs 1937.32,

Annual investment = 12 × monthly payment

= 12 × 1937.32

= 23,247.84 rupees

Answered by efimia
5

Answer:

Rs211344 is invested.

Step-by-step explanation:

Let the monthly salary of Ms Deepti be X.

Therefore, 11%of X=5236.

X=(5236/0.11) = 47600.

Money invested in life insurance policy=19% of 47600=(0.19×47600) =9044.

Money invested in mutual funds=7%of47600 = 0.07×47600 = 3332.

Therefore total amount of money invested per month=(5236+9044+3332) =Rs17612.

Total amount of money invested per year =(17612×12) =Rs 211344

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