Math, asked by kaiyla099, 28 days ago

Ms.Jamison plans to invest $3,800 in two accounts for one year. The first account earns a yearly interest of 3.5%. The second account earns a yearly interest of 6%. How much money does Ms Jamison need to invest in the second account in order to earn $188 in interest from both accounts?

Answers

Answered by IanIsAqt
0

Answer: Let x = amount at 3.5%.

Then the amount at 6% is (3800-x).

The interest from the 3.5% amount is 0.035*x  dollars.

The interest from the 6%   amount is 0.06*x   dollars.

Your equation is

   interest + interest      = total interest,   or

   0.035*x  + 0.06*(3800-x) = 188   dollars.

   x = %28188+-+0.06%2A3800%29%2F%280.035-0.06%29 = 1600.

Answer.  The amount at 3.5% is $1600;  the rest  $3800-$1600 = $2200 is the amount at 6%.

Check.   0.035*1600 + 0.06*2200 = 188 dollars.   ! Correct !

Step-by-step explanation:

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