Question

MSUNG
8. The stoichiometrie numbers of species from left to right in the chemical equation Cu,0 + NO3 + H → Cu?
+ NO + H20 when balanced respectively are
(a) 1, 1, 2, 1.3 (b) 2, 1, 8,4, 1, 4 (c) 2, 2, 12, 4, 2, 6 (d) 3, 2, 14, 6, 2,7
9. The stoichiometric numbers of species from left to right in the chemical equation
Mn + Pb0, +H* →MnO+ Pb2+ + H20
when balanced respectively are
(a) 1. 4. & 1.4.4 (b) 1, 3, 4, 1, 3, 2 (c) 2, 3, 4, 2, 5, 2 (d) 2, 7, 12, 2, 7, 6

Answer 1

Answer:

Balance the following equation. Cu2O + H^ + + NO^ - 3 → Cu^2 + + NO + H2O

Answer 2

• 8. The reaction is-

$Cu+HNO_3\rightarrow Cu(NO_3)_2+NO+H_2O$

• In this reaction, copper reacts with nitric acid to form copper nitrate along with nitrogen oxide and water.

By oxidation number, it can be written as-

$3Cu+8H^++2NO_3^-\rightarrow 3Cu^{+2}+2NO+4H_2O$

The number of species is 3,8,2,3,2,4.

• 9. The reaction is-

$Mn+2PbO+2H^{+}\rightarrow 2Pb^{+2}+MnO+H_2O$

In this reaction, Mn reacts with Lead oxide to form manganese oxide along with water.

The number of species is 1,2,2,2,1,1.