Mt. Everest is at a height of 8850 m. It's base is at an elevation of 5400 m. The temperature here drops at the rate of 1 degree per metres. If the temperature at the base is-5°C, what is the temperature at the top??
[ HINT: Temperature at the base is more than temperature at the top.]
Answers
Step-by-step explanation:
Answer :-
Rs.2000
Explanation :-
Given :
Discount = 17.5%
Cost Price = Rs. 1200
Profit = 37.5%
To Find :
Marked price,MP = ?
Solution :
We know,
\boxed{\sf{}\dfrac{SP\times 100}{100-Discount}}
100−Discount
SP×100
We don’t know selling price,so let’s find out it first.
Selling Price,
\sf{}:\implies \dfrac{CP\times(100+Profit)}{100}:⟹
100
CP×(100+Profit)
\sf{}:\implies \dfrac{1200\times(100+37.5)}{100}:⟹
100
1200×(100+37.5)
\sf{}:\implies \dfrac{1200\times(1137.5)}{100}:⟹
100
1200×(1137.5)
\sf{}:\implies \dfrac{165000}{100}:⟹
100
165000
\sf{}\therefore Rs.1650∴Rs.1650
Therefore,selling price is equal to Rs.1650
So marked price,
\sf{}:\implies\dfrac{1650\times 100}{100-17.5}:⟹
100−17.5
1650×100
\sf{}:\implies\dfrac{165000}{100-17.5}:⟹
100−17.5
165000
\sf{}:\implies\dfrac{165000}{82.5}:⟹
82.5
165000
\sf{}\therefore Rs.2000∴Rs.2000
Hence, marked price is equal to Rs.2000
chal भिखारी