Question

Mt Everest is at the height of 8850 m, its base is at an elevation of 5400m. The temperature here drops at the rate of 1degree per 100m. If the temperature at the base is(-5), what will be the temperature at the top?

Answer 1

Temperature drop from 5400m = 1 degree per 100m

Temperature drop from 5400m = 1 degree per 100mheight of top = 8850 m

Temperature drop from 5400m = 1 degree per 100mheight of top = 8850 mtemperature at base = -5 degree

Temperature drop from 5400m = 1 degree per 100mheight of top = 8850 mtemperature at base = -5 degreeheight of top from base = 8850 - 5400 = 3450m

Temperature drop from 5400m = 1 degree per 100mheight of top = 8850 mtemperature at base = -5 degreeheight of top from base = 8850 - 5400 = 3450mtotal drop in temperature = 3450/100 = 34.5 degree

Temperature drop from 5400m = 1 degree per 100mheight of top = 8850 mtemperature at base = -5 degreeheight of top from base = 8850 - 5400 = 3450mtotal drop in temperature = 3450/100 = 34.5 degreeso temperature at top = -5 - 34.5 = -39.5 degree celsius

Answer 2

☆ Answer ☆

$\sf \green{ -39.5°C}$

☆ Solution ☆

$\rightarrow$ Height of My. Everest from its base = 8850-5400

3450 m

$\rightarrow$ Drop in temperature = 3450/ 100 = 34.5

$\rightarrow$ Temperature at the top = -5°C - (34.5) °C

= -39.5°C

$\fbox\red{Hope It Helps}$